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A 0.01 M solution of MgCl2 is diluted b...

A 0.01 M solution of `MgCl_2` is diluted by adding water . What will happen to its conductivity and molar conductivity ?

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To analyze the effects of dilution on the conductivity and molar conductivity of a 0.01 M solution of MgCl₂, we can break down the solution into clear steps: ### Step 1: Understand the Components - **MgCl₂** dissociates in water to produce magnesium ions (Mg²⁺) and chloride ions (Cl⁻). The dissociation can be represented as: \[ MgCl_2 \rightarrow Mg^{2+} + 2Cl^{-} \] - For every mole of MgCl₂, we get 1 mole of Mg²⁺ and 2 moles of Cl⁻, resulting in a total of 3 moles of ions per mole of MgCl₂. ...
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(a) Apply Kohlrausch law of independent migration of ions, write the expression to determine the limiting molar conductivity of calcium chloride. (b) Given are the conductivity and molar conductivity of NaCI solutions at 298 K at different concentrations : Compare the variation of conductivity and molar conductivity of NaCI solutions on dilution. Give reason. (c) 0.1 M KCI solution offered a resistance of 100 ohms in conductivity cell at 298 K. If the cell constant of the cell is 1.29 cm^(-1) , calculate the molar conductivity of KCI solution.

Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. What will happen to the conductivity of the cell with the dilution ?

Calculating conductivity and molar conductivity: Resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If the resistance of the same cell when filled with 0.02 M KCl solutions 520 Omega and the conductivity of 0.1 KCl solution is 1.29 S m , calculate the conductivity and moalr conductivity of 0.02 M KCl solution. Strategy : Calculate the cell constant with the help of 0.01 M KCl solution (both R and kappa are Known). Use the cell constant to determine the conductivity of 0.02 M KCl solution and finally find its molar conductivity using the molarity

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