How much electricity in terms of Faraday is required to produce `20 g` of `Ca` from molten `CaCl_(2)` ?

Explanation

`Ca^(2+) + 2e^(-) to Ca`
1 mol of Ca i.e., 40 g require electricity = 2 F
20 g of Ca will require electricity = `(2 xx 20)/(40)""F = 1 F`