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The distance between a light source and ...

The distance between a light source and photoelectric cell is d. If the distance is decreased to `(d)/(2)` then

A

The emission of electron per second will be four times.

B

Maximum kinetic energy of photoelectrons will be four times.

C

Stopping potential will remain same

D

The emission of electrons per second will be doubled

Text Solution

Verified by Experts

The correct Answer is:
A, C
Intensity of light `I prop 1/r^2` Also ` I prop N` (Number of photons per second)
`therefor N prop 1/r^2`
Hence, number of emitted electrons will be four times. According Einstein.s photoelectric equation,
`KE_(max) = eV_(s) = h upsilon - phi`
Here, `upsilon` remains constant hence stopping potential (V) will reamain same.
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