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A compound C (molecular formula, C(2)H(4...

A compound C (molecular formula, `C_(2)H_(4)O_(2)`) reacts with Na metal to form a compounds R and evolves a gas which burns with a pop sound. Compound C on treatment with an alcohol A in the presence of an acid form a sweet smelling compound S (molecular formula, `C_(3)H_(6)O_(2))`. On addition of NaOH to C, it also gives R and water.S on treatment with NaOH solution gives back R and A.
Identify C,R,A,S and write down the reactions involved.

Text Solution

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C - Ethanoic acid
R - Sodium salt of ethanoic acid (sodium acetate) and gas evolved is hydrogen
A - Methanol
S - Ester (Methyl acetate)
(a) `underset((C )) (2CH_(3)COOH)+2Na to underset((R ))(2CH_(3)COONa)+H_(2)`
(b) `underset((C ))(CH_(3)COOH)+underset((A))(CH_(3)OH) overset("Conc. "H_(2)SO_(4)) to underset((S))(CH_(3)COOCH_(3))+H_(2)O`
(c )` underset((C ))(CH_(3)COOH)+NaOH overset("Conc. "H_(2)SO_(4))to underset((R )) (CH_(3)COONa)+H_(2)O`
(d) `underset((S))(CH_(3)COOCH_(3))+NaOH to underset((R ))(CH_(3)COONa)+underset((A))(CH_(3)OH)`
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