The rate of a gaseous reaction is given by the is expression k[A][B].If the volume of the reaction vessel is suddenly reduced to `1//4` of the initial volume, the reaction rate relating to original rate will be

Options

A. `1//10`
B. `1//8`
C. 8
D. 16

Answer

d

Explanation

Since active mass = concentration in moles/litre Thus when the volume of the reaction vessel reduces to `1/4^(th)` of its initial volume the molar concentration of each reactant increases four times. Thus
r=k[4A][4B]-16 k [A][B] i.e. 16 times.