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The following graph shows how t(1//2) (h...

The following graph shows how `t_(1//2)` (half-life) of a reactant R changes with the initial reactant concentration `a_0`. The order of the reaction will be

A

0

B

1

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
c
`t_(1//2) prop (1)/(a_0^(n-1)),`
`a_0^(n-1)=a_0`
`therefore` n-1 = 1 `implies` n = 2.
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