Home
Class 12
CHEMISTRY
The rate of a certain reaction is given ...

The rate of a certain reaction is given by, rate = `k[H^(+)]^(n)`. The rate increases 100 times when the pH changes from 3 to 1. The order (n) of the reaction is

A

2

B

0

C

1

D

1.5

Text Solution

Verified by Experts

The correct Answer is:
c
Rate (r) = `k[H^+]^n`
When pH = 3 , `[H^+]` = `10^(-3)`
and when pH = 1 , `[H^+]`=`10^(-1)`
`therefore (r_1)/(r_2)=(k(10^(-3))^n)/(k(10^(-1))^n) implies (1)/(100) =((10^(-3))/(10^(-1)))^n (therefore r_2=100 r_1)`
`implies (10^(-2))^1=(10^(-2))^n implies n=1`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL DYNAMICS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 2: Single Option Correct Type )(2 Marks)|3 Videos

  • CHEMICAL DYNAMICS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 3 : One or More than One Option Correct Type)(2 Marks)|2 Videos

  • CHEMICAL DYNAMICS

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 2 : Single Option Correct Type)(2 Mark)|25 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    MTG-WBJEE|Exercise WB JEE Previous Years Questons (Category 2 : One or More than one Option Correct Type )|3 Videos

  • CHEMICAL ENERGETICS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (ONE OR MORE THAN ONE OPTION CORRECT TYPE )|2 Videos

Similar Questions

Explore conceptually related problems

If rate =k[H^(+)]^(n) and it becomes 100 times when the pH changes from 2 to 1, then the order of reaction is

If (dx)/(dt)=k[H_(3)O^(+)]n and rate becomes 100 times when pH changes from 2 to 1 Hence order of reactions is

If ((dx)/(dt))=k[H^(+)]^(n) and rate becomes 100 times when pH change from 2 to 1. Hence, order is :

If the rate expression for a chemical reaction is given by Rate = K[A]^n[B]^n

if the rate of reaction between A and B is given by rate =k[A] [B^(n)] then the reaction is

The rate of a reaction increases eight times when the concentration of the reactant increases four times. The order of the reaction is

(a) Explain the following terms : (i) Order of a reaction (ii) Molecularity of a reaction (b) The rate of a reaction increases four times when the temperature changes from 300 K to 320 K. Calculate the energy of activation of the reaction, assuming that it does not change with temperature. (R = 8.314 J K^(-1) mol^(-1))

For a reaction,the expression for rate of reaction is given by: R=k[X]^(2 )[Y] .If the concentration of X and Y is increased by 3 times,then what will be the increase in the rate of reaction?