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For the reaction M^X +MnO(4) ^(- ) ...

For the reaction
`M^X +MnO_(4) ^(- ) to MO_3^(-) +Mn^(2+) +1//@O_2` if one mole of `MnO_(4)^(-) ` oxidises 1.67 moles of `M^+` to` MO_3^(-) ` then the value of x in the reaction is

A

5

B

3

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
`overset(+7 )(MnO_(4)^(-) +5e^(-) to Mn^(2+)`
since 1 mole of `MnO_4^(-)` accepts 5 moles of electrons therefore , 5 moles of electrons are lost by 1.67 moles of `M^(x+)`
` therefore ` 1 mole of `M^(x+)` will lose electrons
`= 5 //1.67 = 3 ` moles ( approx )
since ` M^(x+)` changes to `MO_(3)^(-)`
( where O.N of `M= +5 )` by accepting 3 electrons
` therefore x= +5 -3 =+2`
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