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A mole ofN2 H4 loses ten moles of electr...

A mole of`N_2 H_4 `loses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (There is no change in the oxidation number of hydrogen.)

A

`-1`

B

`-3`

C

`+3`

D

`+5`

Text Solution

Verified by Experts

The correct Answer is:
C
`N_2 H_4 - 10 e^(-) toY ` ( with two N atoms )
total O.N of two N atoms in `N_2 H_4` is
`2x +4 =0 or 2x =- 4`
since it loses 10 moles of electrons therefore , total O.N of two N atoms increases by 10 i.e.., the total O.N of two N atoms in
` y=- 4 +10 = + 6`
` therefore O.N ` of each N atom in Y=+3
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One mole of N_(2)H_(4) loses ten moles of electrons of form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y ? (There is no change in the oxidation state of hydrogen.)