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The number of electrons involved in the ...

The number of electrons involved in the reduction of nitrate ion to hydrazine is

A

8

B

7

C

5

D

3

Text Solution

Verified by Experts

The correct Answer is:
B
`NO_3^(- ) to N_2 H_4 `
to balance N atoms multiply `NO_(3)^(- ) ` by 2 we have

To balance O.N add `14 e^(-)` to L.H.S we have
`2NO_(3)^(- ) + 14 e^(- ) to N_2 H_4`
` or NO_(3)^(-) + 7 e^(-) to 1//2 N_2 H_4 `
therefore number of electrons involved in the reduction of ` NO_(3)^(-) ` ions is 7 .
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