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A cell is represented by Zn| Zn((aq))^(+...

A cell is represented by `Zn| Zn_((aq))^(+ +) ||Cu_((aq))^(+ +) | Cu ` given `Cu^(+ +)+2 e^(-) to Cu , E^(@) = + 0.35 V ` and `Zn^(+ +) +2e^(- ) to Zn ,E^@ =- 0.763 `V Calculate emf of the cell and state whether the cell reaction will be spontaneous or non-spontaneous ?

A

1.113, spontaneous

B

`-0.567`, non-spontaneous

C

`-1.113`, non-spontaneous

D

5.678 spontaneous

Text Solution

Verified by Experts

The correct Answer is:
A
Half cell reaction of aode i.e, L.H.S electrons
` Zn-2e^(-) hArr Zn^( + +)`
half cell reaction of cathode i.e., R.H.S electrode
` Cu^( + +) hArr Zn^( ++) +cu`
`E_("cell") ^@ = E_("red ")^(@) ` of R.H.S -` E_("Red ")^@ ` of L.H.S
`= + 0.35 - ( - 0.763 ) = 1.113` volt
since `E_("cell")^@ ` is positive and hence `Delta G ` is negative and therefore teh cell reaction is spontaneous
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