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3.92 g//L of a sample of ferrous a...

3.92 g//L of a sample of ferrous ammonium sulphate reacts completely with 50 mL `(N )/(10 ) KMnO_4` solution the percentage purity of the sample is

A

50

B

`78.4`

C

`80.0`

D

`39.2`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_1 xxV_1 = N_2 xxV_2`
` [FeSO_4 (NH_4)_2 SO_4 .^H_2 O] [KMnO_4]`
` N_1 xx 100 =1/100 =1/10 xx 50 or N_1 =(1)/( 200)`
eq wt of ` FeSO_4 .(NH_4)_2 SO_4 .^H_2 O = Mol wt = 392`
` therefore ` Strength ofpure salt `= 392 xx (1)/(200 ) = 1.96 gL^(-1)`
` therefore ` % purity = `( 1.96 )/ ( 3.92 ) xx 100 =50 % `
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