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given the standard half -cell potent...

given the standard half -cell potentials `(E^@) ` of the following as :
`Zn=Zn^(2+) +2e^(- ) , E^@ = + 0.76 V`
` Fe = Fe^(2+) + we^(-) , E^@ = 0.41 V`
then the standard e,m,f of the cell with the reaction

A

`-0.35 V`

B

`+0.35 V`

C

`+1.17 V`

D

`-1.17 V`

Text Solution

Verified by Experts

The correct Answer is:
B
`Fe^(2+) +Zn to Fe+Zn(2+)`
`therefore ` Standard EMF of the cell
= Oxidation potential of anode + Reduction potential of cathode
`-(0.76 ) + ( -0.41 ) = +0.35 V `
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