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At temperature of 298 K the emf of the f...

At temperature of 298 K the emf of the following electrochemical cell
` Ag_((s)) |Ag^(+ ) (0.1 M ) ||Zn^(2+) (0.1 M ) |Zn_((s))`
will be ( given `E_("cell")^@ =-1.562 V)`

A

`-1.532`V

B

`-1.503 V`

C

`1.532 V`

D

`-3.06 V`

Text Solution

Verified by Experts

The correct Answer is:
A
`2Ag _((s)) to 2Ag^(+) ( 0.1 M ) + 2e^(-)`
`2e^(-) +Zn ^(2+) ( 0.1 M ) to Zn_((s))`
` 2Ag _((s)) +Zn^(2+) (0.1 M ) to Zn_((s))`
` 2Ag_((s)) +Zn^(2+) ( 0.1 M ) to 2Ag ^( +) ( 0.1 M ) + Zn_((s))`
` therefore E_("cell ") =E_("cell")^(@ ) - ( 0.059 1)/( 2 ) log _(10) ([AG^( +)]^2 )/([Zn^(2+)])`
` therefore E_("Cell") = -1.562 - ( 0.0591 )/(2) log_(10) ((0.1 )^2)/( 0.1)`
`= -1.562 - 0.03 lpog_(10) 10^(-1)`
` E_("cell") =-1.562 + 0.03 =- 1.532 V `
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