Home
Class 12
PHYSICS
In the figure shown a ball is suspended ...

In the figure shown a ball is suspended from the ceiling of a room in a uniform electric field of magnitude `2xx10^(4)` V/m . If the mass of the ball is 25 g and the charge on the ball is `3muC` . The angle `theta` is `(g=9.8ms^(-2))`

A

`14^(@)`

B

`22^(@)`

C

`34^(@)`

D

`76^(@)`

Text Solution

Verified by Experts

The correct Answer is:
a

`Tsintheta=qE=3xx10^(-6)xx2xx10^(4)` …. (i)
`Tcostheta=mg=25xx10^(-3)xx9.8` …(ii)
`tantheta=(6xx10^(-2))/(25xx9.8xx10^(-3))`
`=(60)/(25xx9.8)=(12)/(5xx9.8)`
`tantheta=theta=(12)/(49)` radians
`=(12)/(49)xx(180^(@))/(pi)=14^(@)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    MTG-WBJEE|Exercise (WB JEE / WORKOUT )CATEGORY 3 : One or More than One Option Correct Type (2 Marks)|10 Videos
  • ELECTROSTATICS

    MTG-WBJEE|Exercise (WB JEE Previous Years Questions ) CATEGORY 1 : Single Option correct Type|23 Videos
  • ELECTROSTATICS

    MTG-WBJEE|Exercise (WB JEE Previous Years Questions ) CATEGORY 3 : One or More than One Opion correct Type|4 Videos
  • ELECTROMAGNETIC WAVES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3 : ONE OR MORE THAN ONE OPTION CORRECT TYPE)|10 Videos
  • GRAVITATION

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 1: Single Option Correct Type|7 Videos

Similar Questions

Explore conceptually related problems

A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is 9.6xx10^(-16) kg the charge on it and excess number of electrons on the particle are respectivly (g=10m//s^(2))

A charged ball of mass 8.4xx10^(16) kg is found to remain suspended in a uniform electric field of 2xx10^(4) Vm^(-1) . Calculate the charge on the ball. Given g = 10 m//s^(2)

A charged cork ball of mass m = 16 g is suspended from a light string in the presence of a uniform electric field as shown in the figure. When E=(1/2hati+2hatj)N//C , the ball is in equiligrium at the angle of 37^@ . find W if The charge on the ball is Wxx10^(-2)C.

A ball is suspended by a thread from the ceiling of a tram car. The brakes are applied and the speed of the car changes uniformly from 36 kmh^(-1) to zero is 5s . The angle by which the ball deviates from the vertical is (g =10ms^(-2)) .

A "0.50gm" ball carries a charge of magnitude 10 mu C" It is suspended by a string in a downward electric field of intensity "300N/C" .If the charge on the ball is positive,then the tension in the string is g=10ms^(-2)

A charged cork ball of mass m = 16 g is suspended from a light string in the presence of a uniform electric field as shown in the figure. When E=(1/2hati+2hatj)N//C , the ball is in equiligrium at the angle of 37^@ . find W if The tension in the string is Wxx10^(-2)N.

A pendulum bob of mass m = 80 mg, carrying a charge of q=2xx10^(-8)C , is at rest in a horizontal, uniform electric field of E = 20,000 V/m. The tension T in the thread of the pendulum and the angle alpha it makes with vertical, is (take g=9.8m//s^(2) )

A bob of mass m is suspended from the ceiling of a train moving with an acceleration a as shown in figure. Find the angle theta in equilibrium position.

A charged cork ball of mass m is suspended on a light sting in the presence of a uniform electric field as shown in fig. When E=(A hat i+B hat j)NC^(-1) , Where A and B positive numbers, the ball is in equilibirum at theta . Find (a) the charge on the ball and (b) the tension in the string.