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A hollow charged metal sphere has radius...

A hollow charged metal sphere has radius `r`. If the potential difference between its surface and a point at a distance `3r` from the centre is V, then electric field intensity at a distance `3r` is

A

`(V)/(6r)`

B

`(V)/(4r)`

C

`(V)/(3r)`

D

`(V)/(2r)`

Text Solution

Verified by Experts

The correct Answer is:
a
`(1)/(4piepsilon_(0))((q)/(r)-(q)/(3r))=V " or"(2q)/(4piepsilon_(0)3r)=V`
`(q)/(4piepsilon_(0)r)=(3V)/(2)`
`E=(q)/(4piepsilon_(0)(3r)^(2))=(q)/(4piepsilon_(0)(r))xx(1)/(9r)=(3)/(2)Vxx(1)/(9r)=(V)/(6r)`
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