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A parallel plate air capacitor is connec...

A parallel plate air capacitor is connected to a battery. The quantities charge, voltage, electric field and energy associated with this capacitor are given by `Q_0` , `V_0`, `E_0` and `U_0` respectively. A dielectric slab is now introduced to fill the space between the plates with battery still in connection. The corresponding quantities now given by Q, V, E and U are related to the previous one as

A

`QgtQ_(0)`

B

`VgtV_(0)`

C

`EgtE_(0)`

D

`UltU_(0)`

Text Solution

Verified by Experts

The correct Answer is:
a
When battery is in connerction , on inserting a dielectric slab the potential difference between plates of charged capacitor does not change but capacity increases.
As , `C=(Q)/(V)`, when C increases , Q increases
`thereforeQgtQ_(0)` as V- remains the same.
Also `U=(1)/(2)QV`
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