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Electric potential at any point is V = -...

Electric potential at any point is `V = - 5 x + 3y + sqrt(15) z`, then the magnitude of the electric field is

A

`3sqrt(2)`

B

`4sqrt(2)`

C

`5sqrt(2)`

D

7

Text Solution

Verified by Experts

The correct Answer is:
d
Along x - axis , `E_(x)=(dV)/(dx)=-(dV)/(dx)=-(-5)=5`
Along y - axis , `E_(y)=-(dV)/(dy)=-3`
Along Z - axis , `E_(z)=-(dV)/(dz)=-sqrt(15)`
`thereforeE^(2)=E_(x)^(2)+E_(y)^(2)+E_(z)^(2)=(5^(2))+(-3)^(2)+(5^(2))_(-3)^(2)+(-sqrt(15))^(2)`
`rArrE^(2)=25+9+15=49rArrE=7`
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