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The plates of a parallel plate capacitor...

The plates of a parallel plate capacitor with air as medium are separated by a distance of `8 mm`. A medium of dielectric constant 2 and thickness `4 mm` having the same area is introduced between the plates. For the capacitance to remain the same, the distance between the plates is

A

8 mm

B

6 mm

C

4 mm

D

10 mm

Text Solution

Verified by Experts

The correct Answer is:
d
With air , `C=(epsilon_(0)A)/(d)=(epsilon_(0)A)/(8xx10^(-3))=(epsilon_(0)Axx10^(3))/(8)`
Let the new distance =d. mm
Thickness of dielectric medium =4mm
Thickness of air layer `=(d.=4)mm`
`therefore` Capacity `C.=(epsilon_(0)Axx10^(3))/((4)/(2)+(d.-4)/(1))=(epsilon_(0)Axx10^(3))/(d.-2)`
`becauseC=C.or,(epsilon_(0)Axx10^(3))/(8)=(epsilon_(0)Axx10^(3))/((d.-2))or,d.=10mm`
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