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If an=sum(r=0)^n1/(nCr), then sum(r=0)^n...

If `a_n=sum_(r=0)^n1/(nC_r),` then `sum_(r=0)^n r/(nC_r)` equals

A

`a_(n) +1`

B

`a_(n) -1`

C

`a_(n)`

D

`2a_(n)`

Text Solution

Verified by Experts

The correct Answer is:
B
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