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Number of terms in the expansion of (1-x...

Number of terms in the expansion of `(1-x)^(51) (1+x+x^(2) )^(50)` is

A

50

B

51

C

100

D

102

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of terms in the expansion of \((1-x)^{51} (1+x+x^2)^{50}\), we can follow these steps: ### Step 1: Simplify the Expression We start with the expression: \[ (1-x)^{51} (1+x+x^2)^{50} \] ### Step 2: Expand \((1+x+x^2)^{50}\) We can rewrite \(1+x+x^2\) as: \[ 1+x+x^2 = \frac{1-x^3}{1-x} \] Thus, we can express \((1+x+x^2)^{50}\) as: \[ (1+x+x^2)^{50} = \left(\frac{1-x^3}{1-x}\right)^{50} = (1-x^3)^{50} (1-x)^{-50} \] ### Step 3: Combine the Expressions Now substituting back into our original expression: \[ (1-x)^{51} \cdot (1-x^3)^{50} \cdot (1-x)^{-50} \] This simplifies to: \[ (1-x)^{51-50} \cdot (1-x^3)^{50} = (1-x)^{1} \cdot (1-x^3)^{50} \] So we have: \[ (1-x)(1-x^3)^{50} \] ### Step 4: Expand \((1-x^3)^{50}\) Using the binomial theorem, the expansion of \((1-x^3)^{50}\) will have terms of the form: \[ \binom{50}{k} (-x^3)^k = \binom{50}{k} (-1)^k x^{3k} \] where \(k\) can take values from \(0\) to \(50\). ### Step 5: Combine the Terms Now, we need to consider the product: \[ (1-x)(1-x^3)^{50} \] This will yield: \[ 1 \cdot (1-x^3)^{50} - x \cdot (1-x^3)^{50} \] The first term contributes the same number of terms as \((1-x^3)^{50}\), which has \(50 + 1 = 51\) terms. The second term, \(-x(1-x^3)^{50}\), will also contribute \(51\) terms, but they will be of the form \(x^{3k+1}\) for \(k = 0, 1, 2, \ldots, 50\). ### Step 6: Determine Unique Terms Now we need to find the unique terms from both expansions: - The first expansion contributes terms of the form \(x^{3k}\) for \(k = 0, 1, 2, \ldots, 50\) (51 terms). - The second expansion contributes terms of the form \(x^{3k+1}\) for \(k = 0, 1, 2, \ldots, 50\) (51 terms). ### Step 7: Count Total Unique Terms The powers of \(x\) from both expansions are: - From the first: \(0, 3, 6, \ldots, 150\) (which gives us 51 terms). - From the second: \(1, 4, 7, \ldots, 151\) (which also gives us 51 terms). Since the powers \(0, 3, 6, \ldots, 150\) and \(1, 4, 7, \ldots, 151\) do not overlap, the total number of unique terms is: \[ 51 + 51 = 102 \] ### Final Answer Thus, the number of terms in the expansion of \((1-x)^{51} (1+x+x^2)^{50}\) is: \[ \boxed{102} \]
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