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In a first-order reaction, it takes the ...

In a first-order reaction, it takes the reactant 40.5 minutes to be `25%` decomposed. Find the rate constant of the reaction.

Text Solution

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Since the reactant is 25% decomposed in 40.5 min, the remaining reactants is `75%," i.e. "(a-x)=0.75" at "40.5" min."`
`k=(2.303)/(t)log""(a)/(a-x)=(2.303)/("40.5 min")log""(a)/(0.75a)`
`=0.05686log" 1.33 min"^(-1)`
`=0.05686xx0.1249" min"^(-1)`
`=7.1xx10^(-3)" min"^(-1)`
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