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In the binomial expansion of (a-b)^n , n...

In the binomial expansion of `(a-b)^n , ngeq5,` the sum of 5th and 6th terms is zero, then `a/b` equals

A

`(n - 5)/(6)`

B

`(n - 4)/(5)`

C

`(5)/(n - 4)`

D

`(6)/(n - 5)`

Text Solution

Verified by Experts

Given `T_5+T_6=0`
`rArr .^Nc_4a^(n-4)b^4-.^nC_5a^(n-5)b^5=0`
`rArr .^nC_4 a^(n-4)b^4=.^Nc_5 a^(n-5)b^5rArr (a)/(b)=(.^Nc_5)/(.^C_4)=(n-4)/(5)`
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