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Let L be a normal to the parabola y^2=4x...

Let L be a normal to the parabola `y^2=4x`.If L passes through the point (9,6) then L is given by

A

y - x + 3 = 0

B

y + 3x - 33 = 0

C

y + x - 15 = 0

D

y - 2x + 12 = 0

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
Normal to `y^(2) = 4x` is
`y = mx - 2m - m^(3)` which passes through (9,6)
`implies 6 = 9m - 2m - m^(3)`
`implies m^(3) - 7m + 6 = 0`
`implies m = 1,2 - 3`
`:.` Equation of normals are,
y - x + 3 = 0, y + 3x 33 = 0 and 2x 12 = 0
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