On nuclear chlorination, `C_(8), H_(10) (A)` gives a product `(B)` which may be oxidised to `C_(8) H_(5)O_(4)Cl(C). (A)` may alos be chlorinated to give `C_(8) H_(8) Cl_(2)(D), C_(8) H_(6)Cl_(4)(E)`, and `C_(8) H_(4) Cl_(6)(F). (D), (E)` and `(F)` on hydrolysis give halogen-free compounds `(G), (H)`, and `(I)`, respectively. With `CrCO_(2)Cl_(2), (A)` gives `C_(8) H_(6)O_(4)` which is identiacla with `(I)` . Identify wtih `(I)`. Identify the varioius compounds `(A)` to `(J)`.

Explanation

`4 D.U` in `(A)` suggests benzene ring with two `(Me)` groups on `p-` psotion since one product on mono-chlorination `(OMP = 231)`