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product on monobromination of this compo...


product on monobromination of this compound is

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
`b`

It is electrophlic substituion, so electrophilic must be attacked at `o//p-` position due to higher electron density at these positions. Ring `(A)` is activated by `+R` effect of `(NH-)` group, while ring `(B)` has `EW (-overset(O)overset(||)(C)-)` group. So `SE reaaction will take place at `p-` position ring `(A)`, since `o-` position is blocked.
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