Divide `₹ 2340` into three partsnsuch that first part be double that of second part and second pary be `(1)/(3)` of the third part. Find the Third part amount ?

Options

A. `₹780`
B. `₹1170`
C. `₹ 750`
D. `₹ 390`

Explanation

To solve the problem of dividing ₹2340 into three parts where the first part is double that of the second part and the second part is one-third of the third part, we can follow these steps:

### Step 1: Define the Parts
Let the second part be represented as \( x \).

- The first part, being double the second part, will be \( 2x \).
- The third part, being three times the second part (since the second part is one-third of the third part), will be \( 3x \).

### Step 2: Set Up the Equation
Now, we can express the total amount in terms of \( x \):
\[ 2x + x + 3x = 2340 \]

### Step 3: Combine Like Terms
Combine the terms on the left side:
\[ 6x = 2340 \]

### Step 4: Solve for \( x \)
To find \( x \), divide both sides by 6:
\[ x = \frac{2340}{6} = 390 \]

### Step 5: Find Each Part
Now that we have \( x \):
- The second part is \( x = 390 \).
- The first part is \( 2x = 2 \times 390 = 780 \).
- The third part is \( 3x = 3 \times 390 = 1170 \).

### Conclusion
The amount of the third part is ₹1170.

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