An inspector is 228 meter behind the theif . The inspector runs 42 meters and the thief runs 30 meters in a minute . In what time the inspector catch the thief ?

Options

A. 19 minutes
B. 20 minutes
C. 18 minutes
D. 21 minutes

Answer

A

Explanation

Inspector s 228 meter behind the thief and now after some x distance he will catch the theif . So ,
`(x)/(30) = (228 + x)/(42) ` , we will get x = 570m
So time taken by inspector to catch the thief
`= ((228 + 570))/(42) = 19 `minutes
Alternate Method :
Total time to catch = `(("Distance between the two"))/(("Relative speed"))`
`(228)/((42-30)) = (228)/(12) = 19 `minutes