Ashwin has to travel from one point to another point in a certain time . Travelling at a speed of 6 kmph he reaches 40 m late and travelling at a speed of 8 kmph he reaches 12 m earlier . What is the distance between this two points ?

Options

A. 27 km
B. 18 km
C. 5 km
D. 21 km

Answer

D

Explanation

`(d)/(6) - (40)/(60) = (d)/(8) + (12)/(60)`
`(d)/(6) - (d)/(8) = (12)/(60) + (40)/(60)`
`(2d)/(48) = (52)/(60)`
`D = (52 xx 48)/(60 xx 2) = 20.8` = 21 km