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A train of some length passes the platf...

A train of some length passes the platform of length 400 m in 45 seconds . Find the length of train if the speed of train is 66 km/hr .

A

476 m

B

None of these

C

428 m

D

410 m

Text Solution

AI Generated Solution

The correct Answer is:
To find the length of the train, we can follow these steps: ### Step 1: Convert the speed from km/hr to m/s The speed of the train is given as 66 km/hr. We need to convert this speed into meters per second (m/s) using the conversion factor: \[ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} \] So, \[ 66 \text{ km/hr} = 66 \times \frac{5}{18} \text{ m/s} \] Calculating this gives: \[ 66 \times \frac{5}{18} = 18.33 \text{ m/s} \] ### Step 2: Use the formula for distance We know that distance is calculated using the formula: \[ \text{Distance} = \text{Speed} \times \text{Time} \] In this case, the total distance covered by the train while passing the platform is equal to the length of the train (let's denote it as \( L \)) plus the length of the platform (400 m). ### Step 3: Calculate the total distance The train passes the platform in 45 seconds. Therefore, the total distance covered by the train is: \[ \text{Total Distance} = \text{Speed} \times \text{Time} \] Substituting the values we have: \[ \text{Total Distance} = 18.33 \text{ m/s} \times 45 \text{ s} \] Calculating this gives: \[ \text{Total Distance} = 825 \text{ m} \] ### Step 4: Set up the equation The total distance covered by the train is equal to the length of the train plus the length of the platform: \[ L + 400 = 825 \] ### Step 5: Solve for the length of the train Now, we can solve for \( L \): \[ L = 825 - 400 \] Calculating this gives: \[ L = 425 \text{ m} \] ### Conclusion The length of the train is 425 meters. ---

To find the length of the train, we can follow these steps: ### Step 1: Convert the speed from km/hr to m/s The speed of the train is given as 66 km/hr. We need to convert this speed into meters per second (m/s) using the conversion factor: \[ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} \] So, ...
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