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Out if five girls and three boys, four c...

Out if five girls and three boys, four children are to be randomly selected for contest . What is the probability that all the selected children are girls ?

A

`(1)/(14)`

B

`(1)/(7)`

C

`(5)/(17)`

D

`(2)/(17)`

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AI Generated Solution

The correct Answer is:
To find the probability that all selected children are girls from a group of 5 girls and 3 boys, we can follow these steps: ### Step 1: Determine the total number of ways to select 4 children from 8. We have a total of 8 children (5 girls and 3 boys). The number of ways to select 4 children from 8 can be calculated using the combination formula: \[ \text{Total ways} = \binom{8}{4} = \frac{8!}{4!(8-4)!} = \frac{8!}{4! \cdot 4!} \] Calculating this gives: \[ \binom{8}{4} = \frac{8 \times 7 \times 6 \times 5}{4 \times 3 \times 2 \times 1} = 70 \] ### Step 2: Determine the number of ways to select 4 girls from 5. Next, we need to find the number of ways to select 4 girls from the 5 available. This is also calculated using the combination formula: \[ \text{Ways to select girls} = \binom{5}{4} = \frac{5!}{4!(5-4)!} = \frac{5!}{4! \cdot 1!} \] Calculating this gives: \[ \binom{5}{4} = 5 \] ### Step 3: Calculate the probability. Now, we can find the probability that all selected children are girls by dividing the number of ways to select 4 girls by the total number of ways to select 4 children: \[ \text{Probability} = \frac{\text{Ways to select girls}}{\text{Total ways}} = \frac{5}{70} \] ### Step 4: Simplify the probability. We can simplify \(\frac{5}{70}\): \[ \frac{5}{70} = \frac{1}{14} \] ### Final Answer: The probability that all selected children are girls is \(\frac{1}{14}\). ---

To find the probability that all selected children are girls from a group of 5 girls and 3 boys, we can follow these steps: ### Step 1: Determine the total number of ways to select 4 children from 8. We have a total of 8 children (5 girls and 3 boys). The number of ways to select 4 children from 8 can be calculated using the combination formula: \[ \text{Total ways} = \binom{8}{4} = \frac{8!}{4!(8-4)!} = \frac{8!}{4! \cdot 4!} \] ...
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