An urn contains 4 green , 5 blue ,2 red and 3yellow marbles .
If two marbles are drawn at random , what is the proabability that both are red or least one is red ?

Options

A. `(26)/(91)`
B. `(1)/(7)`
C. `(199)/(364)`
D. none of these

Answer

D

Explanation

According to question ,
`n(S) =""^(14)C_(2)=(14!)/((14-2)!2!)=(14xx13)/(2xx1)=91`
`therefore ` probability of at least one red marble
`=1-(""^(12)C_(2))/(""^(14)C_(2))=1-(66)/(91)=(91-66)/(91)=(25)/(91)`