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A bucket contains 8red,3 blue and 5 gree...

A bucket contains 8red,3 blue and 5 green marbles .
If 3 marbles are drawn at random , what is the probability that none is red ?

A

`(3)/(8)`

B

`(1)/(16)`

C

`(1)/(10)`

D

`(3)/(16)`

Text Solution

Verified by Experts

The correct Answer is:
C

`n(S) =""^(16)C_(3) =(16xx15xx14)/(1xx2xx3)=560`
Out of the three drawn marbles none is red clearly they will be either blue or green .
`implies n( E)=""^(8)C_(3)=(8xx7xx6)/(1xx2xx3)=56`
`implies ` Required probability `=(n( E))/(n(S))=(56)/(560)=(1)/(10)`
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