If one cap is picked at random , what is the prababaility that it is either blue or yellow ?

Options

A. `(2)/(9)`
B. `(1)/(4)`
C. `(3)/(8)`
D. `(6)/(11)`

Answer

B

Explanation

Total number of caps = 12
`n(S) =""^(12)C_(1)=12`
Out of (2 blue + 1 yellow ) caps number of ways to pick one cap n(E) `=""^(3)C_(1)=3`
Required probability `P(E) =(n(E))/(n(S))=(3)/(12)=(1)/(4)`