In bag A, no of yellow colored balls are Y and no. of green colored balls balls are g,Number of green colored balls are 4 more than the number of yellow colored balls , when one ball is picked
at random then the probaility of getting black color ball is `(15)/(13)`. the value of Y is `18(2)/(11)`% less than g.
In bag B, number of yellow colored balls is `22(2)/(9)%` more than that of bag A, If two balls are picked at random from bag B then the probability of getting both green color ball is `(4)/(37).` Total number of balls in bag B is 75.
In bag C, the ratio of number of green colored balls and number of black colored balls is 7:5 Total number of green and black colored balls is 36, If one ball is picked at random then the probability of getting one yellow ball is `(7)/(13).`
If x number of yellow balls from bag B are taken placed into bag A and 20% of black balls bag A are taken and placed into in bag B.If pick one ball from bag B then the probability that the ball is of black color is `(11)/(26)` , then find the value of x ?

Options

A. 5
B. 6
C. 3
D. 2

Answer

D

Explanation

After replacement `to`
Yellow no. of balls in bag `B=22x`
Black no . Of balls in bag `B=28+5=33`
Green no. of balls in bag `B=25 `
then ,`(33)/(22-x+33+25)=(11)/(26)`
`(33)/(80-x)=(11)/(26)`
`78=80-x`
` x=2`