In bag A there are 8 red balls ,X green balls and 6 yellow balls,probability of drawing one green ball from bag A is 3/5. bag B there are (X-3) red balls, (X-9) green balls and 6 yellow balls ,2 balls are drawn from bag B. Find the porbability that both the balls are red colour ?

Options

A. `12//63`
B. `13//70`
C. `14//75`
D. `17//70`

Answer

D

Explanation

Probability of drawing one green ball
`implies (x)/(14+x)=(3)/(5)`
`implies 5x=42+3x `
`implies x=2I`
`implies ` green balls = 21
In Bag B
Red balls `=(x-3)=(21-3)=18`
Green balls `=(x-9)=(21-9)=12`
Yellow balls = 6
` therefore` Required probability
`=(""^(18)C_(2))/(""^(36)C_(2))=(18xx17)/(36xx85)=(17)/(70)`