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In a box there are12 blue ,X red balls &...

In a box there are12 blue ,X red balls & green balls , probability of choosing one red ball from the given box is `(1)/(3) ` .Then find the sum of red and blue balls in the box?

A

40

B

24

C

28

D

36

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the information given about the number of balls and the probability of selecting a red ball. ### Step 1: Identify the number of balls We know: - Number of blue balls = 12 - Number of red balls = X (unknown) - Number of green balls = 20 ### Step 2: Calculate the total number of balls The total number of balls in the box can be calculated as: \[ \text{Total balls} = \text{Blue balls} + \text{Red balls} + \text{Green balls} \] \[ \text{Total balls} = 12 + X + 20 \] \[ \text{Total balls} = X + 32 \] ### Step 3: Set up the probability equation The probability of choosing one red ball is given as \( \frac{1}{3} \). The probability can be expressed as: \[ \text{Probability of red ball} = \frac{\text{Number of red balls}}{\text{Total number of balls}} \] Substituting the values we have: \[ \frac{X}{X + 32} = \frac{1}{3} \] ### Step 4: Cross-multiply to solve for X Cross-multiplying gives us: \[ 3X = 1 \cdot (X + 32) \] This simplifies to: \[ 3X = X + 32 \] ### Step 5: Rearrange the equation Now, we will rearrange the equation to isolate X: \[ 3X - X = 32 \] \[ 2X = 32 \] ### Step 6: Solve for X Dividing both sides by 2 gives: \[ X = 16 \] ### Step 7: Find the sum of red and blue balls Now that we have the value of X (the number of red balls), we can find the sum of the red and blue balls: - Number of red balls = 16 - Number of blue balls = 12 Thus, the sum is: \[ \text{Sum of red and blue balls} = 16 + 12 = 28 \] ### Final Answer The sum of the red and blue balls in the box is **28**. ---

To solve the problem step by step, we will use the information given about the number of balls and the probability of selecting a red ball. ### Step 1: Identify the number of balls We know: - Number of blue balls = 12 - Number of red balls = X (unknown) - Number of green balls = 20 ...
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