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ABCD is a trapezium such that AB and CD ...

ABCD is a trapezium such that AB and CD are parallel and `BCbotCD`. if `angleADB=theta`,BC=p and CD=q, then AB is equal to

A

`((p^(2)+q^(2))sintheta)/(pcostheta+qsintheta)`

B

`((p^(2)+q^(2))sintheta)/(p sintheta+qcostheta)`

C

`((p^(2)+q^(2))costheta)/(pcostheta+qsintheta)`

D

`((p^(2)+q^(2))costheta)/(p sintheta+qcostheta)`

Text Solution

Verified by Experts

The correct Answer is:
a
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