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If A+B+C=pi then sin2A+sin2B+sin2C=...

If `A+B+C=pi` then `sin2A+sin2B+sin2C=`

A

`4cosAcosBcosC`

B

`4sinAsinBsinC`

C

`2sinAsinBsinC`

D

`8sinAsinBsinC`

Text Solution

Verified by Experts

The correct Answer is:
B
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