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For a positive integer n , fn(theta)=(ta...

For a positive integer n , `f_n(theta)=(tantheta/2)(1+sectheta)(1+sec2theta)(1+sec4theta)....(1+sec2^ntheta.)`, then

A

`f_(2)((pi)/(16))=1`

B

`f_(3)((pi)/(32))=1`

C

`f_(4)((pi)/(64))=1`

D

`f_(5)((pi)/(128))=1`

Text Solution

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The correct Answer is:
A, B, C, D
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