Home
Class 12
MATHS
The point on the parabola y^(2)=4x at wh...

The point on the parabola `y^(2)=4x` at which it cuts the straight line joining (0,0) and (2,3) is

A

(0,0)

B

(2,3)

C

(16/9,8/3)

D

(1,2)

Text Solution

AI Generated Solution

The correct Answer is:
To find the point on the parabola \( y^2 = 4x \) at which it cuts the straight line joining the points \( (0,0) \) and \( (2,3) \), we can follow these steps: ### Step 1: Find the equation of the line The line passes through the points \( (0,0) \) and \( (2,3) \). We can use the two-point form of the equation of a line: \[ y - y_1 = \frac{y_2 - y_1}{x_2 - x_1} (x - x_1) \] Substituting \( (x_1, y_1) = (0, 0) \) and \( (x_2, y_2) = (2, 3) \): \[ y - 0 = \frac{3 - 0}{2 - 0} (x - 0) \] This simplifies to: \[ y = \frac{3}{2} x \] ### Step 2: Substitute the line equation into the parabola equation Now, we have the parabola \( y^2 = 4x \) and the line \( y = \frac{3}{2} x \). We will substitute the expression for \( y \) from the line into the parabola's equation: \[ \left(\frac{3}{2} x\right)^2 = 4x \] ### Step 3: Simplify the equation Expanding the left side: \[ \frac{9}{4} x^2 = 4x \] To eliminate the fraction, multiply through by 4: \[ 9x^2 = 16x \] ### Step 4: Rearrange the equation Rearranging gives us a standard quadratic equation: \[ 9x^2 - 16x = 0 \] ### Step 5: Factor the equation Factoring out \( x \): \[ x(9x - 16) = 0 \] This gives us two solutions: 1. \( x = 0 \) 2. \( 9x - 16 = 0 \) which gives \( x = \frac{16}{9} \) ### Step 6: Find corresponding \( y \) values Now, we will find the corresponding \( y \) values for both \( x \) values using the line equation \( y = \frac{3}{2} x \): 1. For \( x = 0 \): \[ y = \frac{3}{2} \cdot 0 = 0 \quad \Rightarrow \quad (0, 0) \] 2. For \( x = \frac{16}{9} \): \[ y = \frac{3}{2} \cdot \frac{16}{9} = \frac{48}{18} = \frac{8}{3} \quad \Rightarrow \quad \left(\frac{16}{9}, \frac{8}{3}\right) \] ### Step 7: Conclusion Thus, the points where the line intersects the parabola are: 1. \( (0, 0) \) 2. \( \left(\frac{16}{9}, \frac{8}{3}\right) \) ### Final Answer The points on the parabola \( y^2 = 4x \) at which it cuts the straight line joining \( (0,0) \) and \( (2,3) \) are \( (0, 0) \) and \( \left(\frac{16}{9}, \frac{8}{3}\right) \). ---
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTIONS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (CATEGORY 1 : Single Option Correct Type)|32 Videos
  • CONIC SECTIONS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (CATEGORY 2 : Single Option Correct Type)|5 Videos
  • CONIC SECTIONS

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 2 : Single Option Correct Type)|15 Videos
  • COMPLEX NUMBERS

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 3 : One or More than One Option Correct Type (2 Marks) )|3 Videos
  • DEFINITE INTEGRALS

    MTG-WBJEE|Exercise WE JEE PREVIOUS YEARS QUESTIONS (CATEGORY 3 : ONE OR MORE THAN ONE OPTION CORRECT TYPE)|5 Videos

Similar Questions

Explore conceptually related problems

Find the point on the parabola y=(x-3)^(2) where the tangent is parallel to the line joining (3,0) and (4,1)

The co-ordinates of the point on the parabola y=(x^(2)+10x+3) which is nearest to the straight line y=4x-7 are

Find the coordinates of a point on the parabola y=x^(2)+7x+2 which is closest to the straight line y=3x-3

Find a point on the parabola y=(x-2)^(2) , where the tangent is parallel to the line joining (2, 0) and (4, 4).

The point on the parabola y^(2)=64x which is nearest to the line 4x+3y+35=0 has coordinates

Let (x,y) be any point on the parabola y^(2)=4x. Let P be the point that divides the line segment from (0,0) and (x,y) n the ratio 1:3. Then the locus of P is :

If P is a point on the parabola y = x^2+ 4 which is closest to the straight line y = 4x – 1, then the co-ordinates of P are :

On the parabola y^(2)=64x , find the point nearest to the straight line 4x + 3y - 14 = 0.

Find a point on the parabola y=(x-3)^2 , where the tangent is parallel to the chord joining (3, 0) and (4, 1).