A particle starts from the origin at t=O...

A particle starts from the origin at `t=Os` with a velocity of `10.0 hatj m//s` and moves in the `xy`-plane with a constant acceleration of `(8hati+2hatj)m//s^(-2)`. What time is the `x`-coordinate of the particle `16m`?

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The correct Answer is:

(a) `2s,24m,21.26 " ms "^(-1)`

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