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Obtain the answers to (a) and (b) in Q ....

Obtain the answers to (a) and (b) in Q .15, if the circuit is connected to 110 V, 12 kHz supply. Hence explain the statement that a capacitor is a conductor at very high frequencies. Compare this behaviour with that of a capacitor in d.c. after the steady state.

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(a) `I_(0)=3.88A`
(b) `phi=0.2` and is nearly zero at high frequency. Thus, at high frequency, C acts like a conductor. For a dc circuit, after steady state, `omega=0` and C amounts to an open circuit.
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