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In a plane electromagnetic wave, the ele...

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of `2.0xx10^10 H_z` and amplitude `48V_m^-1`
(a) What is the wavelength o f the wave?
(b) What is the amplitude of the oscillating magnetic field.
(c) Show that the average energy density of the field `E` equals the average energy density of the field `B.[c=3xx10^8 ms^-1]`.

Text Solution

Verified by Experts

(a) `lamda =(c//v) =1.5 xx10^(-2) m`
(b) `B_(0)=(E_(0)//c)=1.6 xx10^(-7) T`
(c ) Energy density in E field: `u_(E) =(1//2)epsi_(0) E^(2)`
Using `E= cB, and c=(1)/(sqrt(mu_(0) epsi_(0)), u_(E)=u_(B)`
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