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50 ml of gas A effuse through a pin -hol...

50 ml of gas A effuse through a pin -hole in 146 second . The same volume of `CO_2` under identical condition effuse in 115 seconds . Calculate the molecular mass of A .

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`("Effusion rate of" CO_(2)) /("Effusion rate of A") = sqrt((M_(A))/(M_(CO_(2))))`
`(50/115)/(50/146) = sqrt((M_(A))/(44)) , (1.27)^(2) = (M_(A))/(44)`
`M_(A) = 71 therefore` Molecular mass of A is 71 .
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