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Find modulus and argument of the complex...

Find modulus and argument of the complex numbers
`z=-1-isqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
`2,(-2pi)/3`
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Knowledge Check

  • The descending order of the principal values of arguments of the complex numbers z_(1) = 1 + i , z_(2) = -sqrt3 + i, z_(3) = 1 + sqrt3 i , z_(4) = 1 - i is

    A
    `z_(3) , z_(2) , z_(1) , z_(4)`
    B
    `z_(2) , z_(3) , z_(1) , z_(4)`
    C
    `z_(3) , z_(1) , z_(2) , z_(4)`
    D
    `z_(4) , z_(1) , z_(3) , z_(2)`

  • (1+isqrt3)^9

    A
    `-2^6`
    B
    `-2^8`
    C
    `-2^9`
    D
    `-2^(12)`

  • The sum of the least positive arguments of the distinct cube roots of the complex number (1-i sqrt3) is

    A
    `(5pi)/(3)`
    B
    `(17pi)/(3)`
    C
    `(23pi)/(3)`
    D
    `(11pi)/(3)`

    • Similar Questions

    Explore conceptually related problems

    Find the modulus and arguments of the complex numbers. (i) (1+i)/(1-i) , (ii) 1/(1+i)

    Represent the complex number z=1+isqrt(3) in the polar form.

    Convert the complex number (-16)/(1+isqrt(3)) into polar form.

    Express the complex numbers modulus -amplitude form -1-isqrt(3)

    The ascending order of the moduli of the complex numbers z_1=1 +I,z_2=1 +2i,z_3=(1-i)/(sqrt(2)),z_4=3+4i is

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