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x^(2)-2x + 3/2=0...

`x^(2)-2x + 3/2=0`

Text Solution

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The correct Answer is:
`1+- sqrt(2)/2i`
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Knowledge Check

  • The equation whose roots are square of the roots of x^(3) - 2x^(2) - 2x + 3 = 0 is

    A
    `x^(3) + 5x^(2) + 10x + 10 = 0`
    B
    `x^(3) + 8x^(2) + 20x + 16 = 0 `
    C
    `x^(3) - 8x^(2) + 16x - 9 = 0`
    D
    `x^(3) + x^(2) - x + 1 = 0`
  • The roots of x^(3) + x^(2) - 2x - 2 = 0 are

    A
    `-1, pm sqrt(2)`
    B
    0,1,2
    C
    `-2, -1, 1`
    D
    `1, pm`i
  • The equation whose roots are reciprocal of 3x^(4) + 2x^(2) - 2x -3 = 0 is

    A
    `x^(4) + 3x^(3) - 2x^(2) + 3x -3 =0`
    B
    `3x^(4) + 2x^(3) - 2x^(2) -3 = 0`
    C
    `3x^(4) - 2x^(3) + 2x^(2) + 3`
    D
    `3x^(4)- 2x^(3) - 2x^(2) +3 = 0`
  • Similar Questions

    Explore conceptually related problems

    The radical centre of the circles x^(2) + y^(2) = 1, x^(2) + y^(2) - 2x - 3 = 0 and x^(2) + y^(2) - 2y - 3 = 0 is

    The radical centre of the circles x^(2) + y^(2) = 1, x^(2) + y^(2) - 2x - 3 = 0 and x^(2) + y^(2) - 2y - 3 = 0 is

    If tangents be drawn to the circle x^(2) + y^(2) = 12 at its point of intersection with the circle x^(2) + y^(2) - 2x - 3y = 0 , the coordinates of their point intersection is

    If the lengths of the tangents drawn from a point P to the three circles x^(2) + y^(2) - 4 = 0, x^(2) + y^(2) -2x + 3y = 0 and x^(2) + y^(2) + 7y -18 = 0 are equal, then the coordinates of P are

    The roots of x^(3) + 2x^(2) - x - 2 = 0 are