Two positively charged particles fixed in place on an x axis. The charges are `q_(1)=1.60 xx 10^(-19)C and q_(2)=3.20xx10^(-19)C`, and the particle separation is R = 0.0200m. What are teh magnitude and direction of the electrostatic force `vecF_(12)` on particle 1 from particle 2?

Explanation

To find the magnitude and direction of the electrostatic force \( \vec{F}_{12} \) on particle 1 from particle 2, we can use Coulomb's Law. The formula for the electrostatic force between two point charges is given by:

\[ F = \frac{1}{4 \pi \epsilon_0} \frac{|q_1 q_2|}{R^2} \]

where:
- \( F \) is the magnitude of the force between the charges,
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