An electron is released from rest in a uniform electric field of magnitude `2.00 xx 10^(4) N//C` . (a) Calculate the acceleration of the electron. (Ignore gravitational) (b) How much time does the electron take to reach 1.00 % of the speed of light ?

Explanation

Let's solve the problem step by step.

### Given Data:
- Electric field (E) = \(2.00 \times 10^4 \, \text{N/C}\)
- Charge of electron (q) = \(-1.6 \times 10^{-19} \, \text{C}\) (the negative sign indicates it's an electron)
- Mass of electron (m) = \(9.1 \times 10^{-31} \, \text{kg}\)
- Speed of light (c) = \(3.00 \times 10^8 \, \text{m/s}\)

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