A uniform electric field exists in a region between two oppositely charged plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, 3.0 cm away, in a time `1.5 xx 10^(-8) s`. Just as the electron strikes the second plate, what are the its (a) momentum magnitude and (b) kinetic energy ? (c ) What is the magnitude of the electric field `vec(E)` ?

Explanation

To solve the problem step by step, we will find the momentum magnitude, kinetic energy, and the magnitude of the electric field.

### Given Data:
- Distance between plates, \( s = 3.0 \, \text{cm} = 3.0 \times 10^{-2} \, \text{m} \)
- Time taken, \( t = 1.5 \times 10^{-8} \, \text{s} \)
- Mass of electron, \( m = 9.1 \times 10^{-31} \, \text{kg} \)

### Step 1: Calculate the acceleration of the electron
...